sarawoodsgirl
contestada

A two-digit locker combination is made up of nonzero digits and no digit is repeated in any combination.

Event A= the first digit is 1

Event B= the second digit is even

If a combination is picked at random with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?

Respuesta :

konrad509
[tex]|\Omega|=9\cdot8=72\\ A\cap B=\{(1,2),(1,4),(1,6),(1,8)\}\\ |A\cap B|=4\\\\ P(A\cap B)=\dfrac{4}{72}=\dfrac{1}{18}\Rightarrow \text{A}[/tex]
isabelbrandt3

Answer:

I'm doin the quiz now and I think the answer is A. 1/18

Step-by-step explanation:

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