Respuesta :
[tex]|\Omega|=9\cdot8=72\\
|A\cap B|=1\cdot3=3\\\\
P(A \cap B)=\dfrac{3}{72}=\dfrac{1}{24}\Rightarrow \text{A}[/tex]
The value of P(A and B) is 1/24 if the event A is defined as choosing 6 as the first digit, and event B is defined as choosing a number less than 4 as the second digit option (A) is correct.
What is probability?
It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
Event A: choosing 6 as the first digit.
Event B: choosing a number less than 4 as the second digit
Total outcomes = 8×9 = 72
Total favourable outcomes = 3×1 = 3
P(A and B) = 3/72 = 1/24
Thus, the value of P(A and B) is 1/24 if the event A is defined as choosing 6 as the first digit, and event B is defined as choosing a number less than 4 as the second digit option (A) is correct.
Learn more about the probability here:
brainly.com/question/11234923
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