House numbers along the street consist of two-digit numbers. Each house number it’s made up of nonzero digits, and no digit in a house number is repeated.

Event A is defined as choosing 6 as the first digit, and event B is defined as choosing a number less than 4 as the second digit.

A house Number along the street is picked at random, with each number being equally likely a no repeated digits in a number, what is P(A and B) expressed in simplest form?

A. 1/24

B. 1/9

C. 3/8

D. 1/2

Respuesta :

[tex]|\Omega|=9\cdot8=72\\ |A\cap B|=1\cdot3=3\\\\ P(A \cap B)=\dfrac{3}{72}=\dfrac{1}{24}\Rightarrow \text{A}[/tex]

The value of P(A and B) is 1/24 if the event A is defined as choosing 6 as the first digit, and event B is defined as choosing a number less than 4 as the second digit option (A) is correct.

What is probability?

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We have:

Event A: choosing 6 as the first digit.

Event B: choosing a number less than 4 as the second digit

Total outcomes = 8×9 = 72

Total favourable outcomes = 3×1 = 3

P(A and B) = 3/72 = 1/24

Thus, the value of P(A and B) is 1/24 if the event A is defined as choosing 6 as the first digit, and event B is defined as choosing a number less than 4 as the second digit option (A) is correct.

Learn more about the probability here:

brainly.com/question/11234923

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