Respuesta :
[tex]P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\
|\Omega|=20\cdot19=380\\
|A|=6\cdot19=114\\
|A\cap B|=6\cdot5=30\\\\
P(A)=\dfrac{114}{380}=\dfrac{3}{10}\\
P(A \cap B)=\dfrac{30}{380}=\dfrac{3}{38}\\\\
P(B|A)=\dfrac{\dfrac{3}{38}}{\dfrac{3}{10}}\\\\
P(B|A)=\dfrac{3}{38}\cdot\dfrac{10}{3}=\dfrac{5}{19}\Rightarrow \text{B}
[/tex]