Answer:
[tex]\Delta _fH=-66.03kJ[/tex]
Explanation:
Hello,
In this case, by knowing the enthalpy of formation of the copper (II) chloride is -220.1kJ/mol and there are 0.3 moles of such compound, the resulting whole energy is obtained by multiplying those values as the moles define the total energy as shown below:
[tex]\Delta _fH=-220.1\frac{kJ}{mol}*0.30mol\\ \Delta _fH=-66.03kJ[/tex]
Best regards.