Respuesta :

[tex]-8x^2+54x+140 [/tex]
[tex]-2(4x^2-27x-70)[/tex]

Start by factoring -2 out of all three terms:


-8x2 + 54x + 140 => -2(4x^2 - 27x - 70)


Applying the quadratic formula: b^2 - 4ac becomes (-27)^2 - 4(4)(-70), or 1849.

Because this discriminant is +, this quadratic has two real, unequal roots. They are:


-(-27) plus or minus sqrt(1849) 27 plus or minus 43

x = ------------------------------------------------ = ---------------------------------- =

2(4) 8


= {70/8, -2}


Thus, -8x2 + 54x + 140 factors into -2(x+2)(4x-35)