anahi1851 anahi1851
  • 08-07-2018
  • Mathematics
contestada

rewrite sin^4xtan^2x in terms of the first power of the cosine

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DeanR
DeanR DeanR
  • 08-07-2018
[tex]\sin ^4 x \tan ^2 x = \dfrac{\sin ^4 x\ \sin ^2 x }{\cos ^2 x} = \dfrac{\sin^6 x}{\cos ^2 x} = \dfrac{(\sin ^2 x)^3}{\cos^2 x}=\dfrac{(1-\cos^2 x)^3}{\cos^2 x}[/tex]
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