What is the mass of ammonium nitrate in 250 mL of a 75% by mass solution (density = 1.725 g/mL)?

Question

contestada

Respuesta :

SvetkaChem SvetkaChem · Answer 1 · 2018-07-08T18:28:01+02:00

1) We need to find mass of the solution

m=D*V
D= 1.725 g/mL
V= 250 mL
m=1.725 g/mL*250 mL= 431.25 g

2) 75% = 0.75
0.75*431.25 ≈ 323 g of NH4NO3

Answer Link

OlaMacgregor OlaMacgregor · Answer 2 · 2019-07-01T06:58:44+02:00

Explanation:

Density is the mass present in per unit volume.

Mathematically, Density = [tex]\frac{mass}{volume}[/tex]

Therefore, first calculate the mass of solution as follows.

Density = [tex]\frac{mass}{volume}[/tex]

1.725 g/mL = [tex]\frac{mass}{250 mL}[/tex]

mass = 431.25 g

Now, calculate mass of ammonium nitrate as follows.

Percentage by mass = [tex]\frac{\text{mass of ammonium nitrate}}{\text{mass of solution}} \times 100[/tex]

75 = [tex]\frac{\text{mass of ammonium nitrate}}{431.25g} \times 100[/tex]

Mass of ammonium nitrate = 323.43 g

Thus, we can conclude that mass of ammonium nitrate is 323.43 g.