Answer:
The system of equations are [tex]y_1=\log(2x+1)[/tex] and [tex]y_2=3x-2[/tex]
B is correct.
Step-by-step explanation:
Given: [tex]\log(2x+1)=3x-2[/tex]
We are given a equation of log and linear. We need to make system of equation.
We will separate left side and right side function.
[tex]\text{Left Side}=y_1[/tex]
[tex]\text{Right Side}=y_2[/tex]
[tex]y_1=\log(2x+1)[/tex]
[tex]y_2=3x-2[/tex]
The system of equations are [tex]y_1=\log(2x+1)[/tex] and [tex]y_2=3x-2[/tex]
We get two new function with x and y.
Hence, The system of equations are [tex]y_1=\log(2x+1)[/tex] and [tex]y_2=3x-2[/tex]
