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Which lines are perpendicular to the line y - 1 = 1/3(x+2)? Check all that apply.

A. y + 2 = -3(x-4)

B. y - 5 = 3(x+11)

C. y = -3x - 5/3

D. y = 1/3x - 2

E. 3x + y = 7

Respuesta :

DeanR
The slope of the given line is 1/3.

The perpendiculars all have the negative reciprocal slope, -3.

A. y + 2 = -3(x-4)

Yes, slope -3.

B. y - 5 = 3(x+11)

No, slope 3.

C. y = -3x - 5/3

Yes, slope -3.

D. y = 1/3  x - 2

No, that's slope 1/3.

E. 3x + y = 7

That's

y = -3x + 7

Another slope -3, Yes.
abidemiokin

The lines that are perpendicular to the line y - 1 = 1/3(x+2) are y + 2 = -3(x-4) and 3x + y = 7

The equation of a line in point-slope form is expressed as:

[tex]y-y_0 = m(x-x_0)[/tex]

m is the slope of the line

(x0, y0) is the point on the line

Given the equation y - 1 = 1/3(x+2), compared to the general formula above, we will see that:

m = 1/3

If two lines are perpendicular, the product of their slope must be -1

Let M the slope of the line perpendicular;

mM = -1

1/3 M = -1

M = -3

Hence all the lines that are perpendicular to the line y must have a slope of -3.

The equations that falls in this categories are;

y + 2 = -3(x-4) and 3x + y = 7

learn more here: https://brainly.com/question/23343212

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