When comparing concentration and volume, we can use the equation:
[tex]M_{1} V_{1} = M_{2} V_{2} [/tex]
**Note: the volume in this equation is in liters. Be sure to convert mL to L by dividing by 1000.
Now let's plug in the values that were given to us in the equation (using 0.050L for 50 mL and 0.200L for 200 mL):
[tex](1.50M)(0.050L)= M_{2}(0.200L) [/tex]
Then we can solve for [tex] M_{2} [/tex]:
[tex] \frac{(1.50M)(0.050L)}{(0.200L)}= M_{2} [/tex]
[tex] M_{2}=0.375M [/tex]
So now we know that the resulting solution has a molarity of 0.375 M.
