Answer: 585 J
Explanation:
We can calculate the work done during segment A by using the work-energy theorem, which states that the work done is equal to the gain in kinetic energy of the object:
[tex]W=K_f -K_i[/tex]
where Kf is the final kinetic energy and Ki the initial kinetic energy. The initial kinetic energy is zero (because the initial velocity is 0), while the final kinetic energy is
[tex]K_f =\frac{1}{2}mv^2[/tex]
The mass is m=1.3 kg, while the final velocity is v=30 m/s, so the work done is:
[tex]W=K_f = \frac{1}{2}(1.3 kg)(30 m/s)^2=585 J[/tex]
