For this problem, we are going to be using multiplication and cancelling units. We need to first find the molar weight of mercury, found on the periodic table as 200.59g/mol.
So then we set up the equation:
[tex] \frac{1.20* 10^{22}atoms }{1}* \frac{1mole}{6.022* 10^{23}atoms } * \frac{200.59gHg}{1mole} [/tex]
Then we multiply straight across to find the mass in grams:
[tex] \frac{1.20* 10^{22}atomsHg }{1}* \frac{1 mole}{6.022* 10^{23}atoms } * \frac{200.59g}{1mole} = 3.99g Hg[/tex]
So now we know that the mass of this sample is 3.99g Hg.
