Respuesta :
Hello!
To find this probability, we add the two probabilities we are given.
First of all, we have the probability of rolling a 2.
[tex] \frac{2}{6}
[tex] \frac{1}{2} [/tex]=[tex] \frac{3}{6} [/tex]
And the probability of getting heads as seen above.
Now we add our two fractions.
[tex] \frac{2}{6}(\frac{3}{6})=\frac{5}{6} [/tex]
Therefore, our probability is 5/6, or about 83%.
I hope this helps!
To find this probability, we add the two probabilities we are given.
First of all, we have the probability of rolling a 2.
[tex] \frac{2}{6}
[tex] \frac{1}{2} [/tex]=[tex] \frac{3}{6} [/tex]
And the probability of getting heads as seen above.
Now we add our two fractions.
[tex] \frac{2}{6}(\frac{3}{6})=\frac{5}{6} [/tex]
Therefore, our probability is 5/6, or about 83%.
I hope this helps!
The probability of rolling a 2 (1 number) in a 6 sided die = 1/6
A coin has two sides, and so the probability of getting a heads = 1/2
Add the two fractions together
(1/6) + (1/2)
(1/6)(2/2) = 2/12
(1/2)(6/6) = 6/12
2/12 + 6/12 = 8/12
Simplify 8/12
(8/12)/(4/4) = 2/3
The probability of rolling a 2 and getting heads is 2/3
hope this helps
A coin has two sides, and so the probability of getting a heads = 1/2
Add the two fractions together
(1/6) + (1/2)
(1/6)(2/2) = 2/12
(1/2)(6/6) = 6/12
2/12 + 6/12 = 8/12
Simplify 8/12
(8/12)/(4/4) = 2/3
The probability of rolling a 2 and getting heads is 2/3
hope this helps