Respuesta :
Answer:
YZ < ZX < XY
Step-by-step explanation:
In a triangle the side opposite to largest interior angle is largest, opposite to medium interior angle is medium and opposite to smallest interior angle is smallest.
Given,
In triangle XYZ,
m∠X = 51°, m∠Y = 59°, and m∠Z = 70°,
Since, 51° < 59° < 70°,
⇒ m∠X < m∠Y < m∠Z
Also, sides YZ, ZX and XY are the opposite sides of the angles X, Y and Z respectively,
Hence, by the above property,
YZ < ZX < XY
Which is the required order.
The list of the sides of ∆XYZ in order from shortest to longest is [tex]\rm YZ < ZX < XY[/tex] and this can be determined by using the given data.
Given :
In triangle XYZ, m∠X = 51, m∠Y = 59, and m∠Z = 70.
The following steps can be used in order to determine the list the sides of ∆XYZ in order from shortest to longest:
Step 1 - Remember the opposite side length of the angle which is the largest is the largest.
Step 2 - Now, according to the given data, the list of the angles in order from shortest to largest is:
[tex]\rm \angle X < \angle Y < \angle Z[/tex]
Step 3 - So, the list of the sides of ∆XYZ in order from shortest to longest is:
[tex]\rm YZ < ZX < XY[/tex]
For more information, refer to the link given below:
https://brainly.com/question/15767203
