Respuesta :
[tex]x^2 + 5x =150[/tex]
[tex]x^2 + 5x -150 = 0[/tex]
[tex](x-10)(x+15)= 0[/tex]
Two roots, x=10 and x=-15
Positive root: x=10
Check: 10^2 + 5(10) = 150, good
[tex]x^2 + 5x -150 = 0[/tex]
[tex](x-10)(x+15)= 0[/tex]
Two roots, x=10 and x=-15
Positive root: x=10
Check: 10^2 + 5(10) = 150, good
To solve this equation, we can solve it like it is a quadratic (because it is). To solve it like it's a quadratic, we need to get one side equal to 0. We can do that by subtracting 150 from each side. That gives us x² + 5x -150 = 0. Now, we can factor the equation. Factoring it gives us (x-10)(x+15) = 0. Now, using the zero-product property, we can conclude the the roots for this equation are x = 10, -15. But, since the question is only asking us for the positive root, the answer is x = 10.