bearing in mind that parallel lines have the same exact slope, wait a minute, what is the slope of that line in the graph anyway?
[tex]\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad
(\stackrel{x_2}{3}~,~\stackrel{y_2}{0})
\\\\\\
% slope = m
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-2}{3-0}\implies \cfrac{-2}{3}[/tex]
