Respuesta :

[tex]\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ ------\\ r=2\\ \theta =\frac{6\pi }{5} \end{cases}\implies s=2\cdot \cfrac{6\pi }{5}\implies s=\cfrac{12\pi }{5}[/tex]

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