notice, is just a pyramid's net, just like the one we saw before, it has a square in its base and 4 triangular faces.
so we do the same, get the area of each, sum them up.
[tex]\bf \stackrel{square}{(3\cdot 3)}~~+~~\stackrel{4~triangles}{4\left[\cfrac{1}{2}(3)(4) \right]}\implies 9~~+~~24\implies 33[/tex]
