Respuesta :
First you should see that the 2s cancel out. The equation becomes:
[tex]ln( e^{ln(5x)} ) = ln15[/tex]
Use the laws of logarithms, knowing that ln(e) = 1.
[tex]ln(5x) = ln(15) \\ 5x = 15 \\ x = 3[/tex]
The answer is B.
Hopefully this helps!
[tex]ln( e^{ln(5x)} ) = ln15[/tex]
Use the laws of logarithms, knowing that ln(e) = 1.
[tex]ln(5x) = ln(15) \\ 5x = 15 \\ x = 3[/tex]
The answer is B.
Hopefully this helps!
Answer:
x=3
Step-by-step explanation:
Given in an equation as
[tex]2 ln e^ln5x=2 ln 15[/tex]
Divide 2 to get
[tex]ln e^ln5x= ln 15[/tex]
Using log rules for exponents we get
ln 5x = ln 15
Cancel ln to get
[tex]5x=15x=3[/tex]
Hence solutin is x=3
