[tex]\bf \cfrac{1}{x^2+2x+1}-\cfrac{1}{x^2+x-2}\implies \cfrac{1}{(x+1)(x+1)}-\cfrac{1}{(x+2)(x-1)} \\\\\\ \textit{therefore our LCD is }(x+1)(x+1)(x+2)(x-1) \\\\\\ \cfrac{(x+2)(x-1)~~-~~(x+1)(x+1)}{(x+1)(x+1)(x+2)(x-1)} \\\\\\
\cfrac{x^2+x-2~~-~~ (x^2+2x+1)}{(x+1)^2(x+2)(x-1)}\implies \cfrac{x^2+x-2~~-~~ x^2-2x-1}{(x+1)^2(x+2)(x-1)} \\\\\\ \cfrac{-x-3}{(x+1)^2(x+2)(x-1)}[/tex]
