Respuesta :

DeanR
Point A is (-2,2) and point C is(3,0) so the midpoint is

[tex]\left( \dfrac{-2 + 3}{2}, \dfrac{2 + 0}{2} \right) = \left( \dfrac 1 2, 1 \right)[/tex]

Choice A


vijayhalder031

The coordinates of midpoint of AC is M(x,y) = [tex][\frac{1}{2},1][/tex]

Concept:

  • Firstly we will find the coordinates of A & C.
  • We will apply midpoint formula to find the midpoint of AC.

How to solve the given question?

  • From the figure, Coordinates of A are (-2,2) and C are (3,0)
  • If M is the midpoint of AC, then by midpoint formula,
    M(x,y) = [tex][\frac{x_1 + x_2}{2},\frac{y_1+y_2}{2} ][/tex]
    ∴ M(x,y) = [tex][\frac{-2+3}{2} , \frac{2+0}{2} ][/tex]
    ∴ M(x,y) = [tex][\frac{1}{2},1][/tex]

Thus, the coordinates of midpoint of AC is M(x,y) = [tex][\frac{1}{2},1][/tex]

Learn more about midpoint here:

https://brainly.com/question/5566419

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