Respuesta :
F (x,y) = 2.30x + 3.10y
The constraints are described with the following inequalities:
2x + 2y < = 120
3x + 4y < = 160
The corner points are: ( 0, 40) and (40/0.75, 0)
F (0,40) = 3.10 * 40 =$124
F (40/0.75,0) = (40/0.75) * 2.30 = $122.67
To maximize the profit they should sell 40 Turkey Specials.
So your answer should be C.
The constraints are described with the following inequalities:
2x + 2y < = 120
3x + 4y < = 160
The corner points are: ( 0, 40) and (40/0.75, 0)
F (0,40) = 3.10 * 40 =$124
F (40/0.75,0) = (40/0.75) * 2.30 = $122.67
To maximize the profit they should sell 40 Turkey Specials.
So your answer should be C.
Answer:
The required constraints are:
[tex]2x+2y\leq120[/tex]
[tex]3x+4y\leq160[/tex]
[tex]x\geq0[/tex]
[tex]y\geq0[/tex]
Step-by-step explanation:
Consider the provided information.
Let, x is the number of roast beef specials and y is the number of turkey specials.
The profit from roast beef special is $2.30 per sandwich, the profit from turkey special is $3.10 per sandwich.
The profit function will be:
[tex]P(x,y)=2.3x+3.10y[/tex]
The bread slices constraint will be:
The roast beef special uses two slices of bread and the turkey special uses two slices of bread. The deli has 120 slices of bread.
[tex]2x+2y\leq120[/tex]
The cheese slices constraint will be:
The roast beef special uses three slices of cheese and the turkey special uses four slices of cheese. The deli has 160 slices of cheese.
[tex]3x+4y\leq160[/tex]
The number of both sandwiches must be greater than zero.
Thus, the constraint will be:
[tex]x\geq0[/tex]
[tex]y\geq0[/tex]
Therefore, the required constraints are:
[tex]2x+2y\leq120[/tex]
[tex]3x+4y\leq160[/tex]
[tex]x\geq0[/tex]
[tex]y\geq0[/tex]