Respuesta :
A line through two points A, B can be found by the point-slope form of the formula:
(y-ya)=m(x-xa)............(1)
and
m=(yb-ya)/(xb-xa).......(2)
where A(xa,ya), B(xb,yb) and m is the slope between points A & B.
Substituting
A(xa,ya)=A(1,3)
B(xb,yb)=B(0,2)
From (2)
m=(yb-ya)/(xb-xa)
=(2-3)/(0-1)
=-1/(-1)
=1
Substitute in (1) : (y-ya)=m(x-xa)
y-3=1(x-1)
Distribute and simplify
y=x-1+3=x+2
or
y=x+2 .................(3a) equation required in slope-intercept form
x-y+2=0...............(3b) equation in standard form
(y-ya)=m(x-xa)............(1)
and
m=(yb-ya)/(xb-xa).......(2)
where A(xa,ya), B(xb,yb) and m is the slope between points A & B.
Substituting
A(xa,ya)=A(1,3)
B(xb,yb)=B(0,2)
From (2)
m=(yb-ya)/(xb-xa)
=(2-3)/(0-1)
=-1/(-1)
=1
Substitute in (1) : (y-ya)=m(x-xa)
y-3=1(x-1)
Distribute and simplify
y=x-1+3=x+2
or
y=x+2 .................(3a) equation required in slope-intercept form
x-y+2=0...............(3b) equation in standard form
Answer:
Indicate the equation of the line meeting the given conditions. Put the equation in standard form.
Containing A (1, 3) and B (0, 2)
x-y=-2
Step-by-step explanation: