Respuesta :
Just put the people attended the ceremony as a constant.
v(x) = 5(x − 1) + 20;
v(x) = 5(x − 1) + 20;
For this case, the first thing we must do is define variables.
We have then:
x: number of days
v (x): total number of visitors including the ceremony.
The function that represents the problem is:
[tex]v (x) = 5 (x - 1) + k [/tex]
Where,
k: number of visitors on the first day.
To find the value of k we substitute the following pair ordered in the function:
[tex](x, v (x)) = (1, 20) [/tex]
We have then:
[tex]20 = 5 (1 - 1) + k 20 = 5 (0) + k 20 = 0 + k 20 = k[/tex]
Then, the function is:
[tex]v (x) = 5 (x - 1) + 20 [/tex]
Answer:
the function that shows total visitors, including the ceremony is:
[tex]v (x) = 5 (x - 1) + 20[/tex]
We have then:
x: number of days
v (x): total number of visitors including the ceremony.
The function that represents the problem is:
[tex]v (x) = 5 (x - 1) + k [/tex]
Where,
k: number of visitors on the first day.
To find the value of k we substitute the following pair ordered in the function:
[tex](x, v (x)) = (1, 20) [/tex]
We have then:
[tex]20 = 5 (1 - 1) + k 20 = 5 (0) + k 20 = 0 + k 20 = k[/tex]
Then, the function is:
[tex]v (x) = 5 (x - 1) + 20 [/tex]
Answer:
the function that shows total visitors, including the ceremony is:
[tex]v (x) = 5 (x - 1) + 20[/tex]