To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
[tex] \frac{2}{x+2}+\frac{1}{5}=\frac{6}{x+5} [/tex]
2. You need to sum the fractions located on the left member, as following:
[tex] \frac{10+(x+2)}{5(x+2)}=\frac{6}{x+5} [/tex]
[tex] x=(12+x)(x+5)=6(5x+10) [/tex]
3. Simplify it and you will obtain a quadratic equation. Solve it by factor out [tex] x [/tex]:
[tex] x^{2} -13x=0\\ x(x-13)=0\\ x=0; x=13 [/tex]
Therefore, the answer is: [tex] x=0; x=13 [/tex]
