The edge length of the cube is "1.71 cm" and the further calculation can be defined as follows:
Given:
Aluminum Density
Aluminum weighs
A substance's density is defined as its mass per unit volume.
Put the value into the above-given formula:
[tex]= \bold{\frac{13.5}{2.70} \ \frac{g}{\frac{g}{cm^3}}}\\\\= \bold{\frac{13.5}{2.70} \ cm^3}\\\\= \bold{\frac{135}{27} \ cm^3}\\\\=\bold{ 5 \ cm^3}\\[/tex]
[tex]\bold{\therefore}[/tex]
The volume of cube = [tex]\bold{length^3}[/tex]
[tex]\bold{\because}[/tex]
The Length of the cube = [tex]\bold{ volume^{\frac{1}{3} } }[/tex]
[tex]=\bold{5^{\frac{1}{3}}}\\\\ =\bold{1.70999\ cm \approx 1.71\ cm}[/tex]
So, The edge length of the cube "1.71 cm".
Learn more:
edge length: brainly.com/question/11425030
