It has been found that the average number of daily phone calls C between two cities is directly proportional to the product of the populations P1 and P2 of the two cities and inversely proportional to the square of the distance d between the cities. That is, C=(kP1P2)/(d^2).

The distance between Albany, New York, and Cleveland, Ohio, is about 480 miles. If the average number of daily phone calls between the cities is 250,000, find the value of k and write the equation of variation. Round to the nearest thousandth. The population of Albany and Cleveland is 95,000 and 2,900,000 respectively.

Respuesta :

Hello.

427000 = k(777000)(3695000)/420^2 


427000 = k(16275595.24) 


k = 427000/16275595.25 

 k = .0262355996

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Answer:

k = 0.209

Step-by-step explanation:

The given expression in the question is C = [tex]\frac{kP_{1}P_{2}}{d^{2} }[/tex]

Where [tex]P_{1}[/tex] and [tex]P_{2}[/tex] are the populations of the two cities and d is the distance between the cities.

If the distance between the cities d is 480 miles

Population of the cities are [tex]P_{1}[/tex] = 95000 and [tex]P_{2}[/tex]=2900000 respectively.

And average number of the daily phone calls is 250000.

Then we have to find the value of k.

C = [tex]\frac{kP_{1}P_{2}}{d^{2} }[/tex]

250000 = [tex]\frac{k\times 95000\times 2900000}{(480)^{2} }[/tex]

[tex]k=\frac{250000\times (480)^{2} }{95000\times 2900000}[/tex]

[tex]k=\frac{25\times 48\times 48}{9500\times 29}[/tex]

k = 0.2091 ≈ 0.209

k = 0.209 is the answer.