Respuesta :
the picture in the attached figure
we know that
In a Rhombus the diagonals are perpendicular bisectors of each other
so
LP=PN
and
LP=LN /2
LP=28 /2-------->LP=14 cm
the answer is
Lp=14 cm

the picture in the attached figure
we know that
In a Rhombus the diagonals are perpendicular bisectors of each other
so
LP=PN
and
LP=LN /2
LP=28 /2-------->LP=14 cm
the answer is
Lp=14 cm