The decay of 601 mg of an isotope is described by the function A(t)= 601e-0.019t, where t is time in years. Find the amount left after 34 years. Round your answer to the nearest mg. Show all of your work for full credit. (5 points)
We already have the formula given to us. Now we just have to solve for the amount left after we sub in 34 for the t in the equation. [tex]A(t)=601(e^{(-.019)(34)})[/tex] which simplifies to [tex]A(t)=601(e^{-.646})[/tex]. Raise e to that exponent to get A(t) = 601(.5241381418). Doing the multiplication we get that the amount left after 34 years is 315 mg
