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kishonwinston
In this quadratic function the 0's are where x = -9 and 9. They both have multiplicity of 1. This is just how many times hey occor in the polynomial. If grouped they will have an exponent.

Answer: The zeroes are -9,-9, 9, 9, 9.

Step-by-step explanation:

Since we have given that

[tex]f(x)=3(x+9)^2(x-9)^3[/tex]

We need to find the zeroes and the multiplicity.

As we can see that

(x+9) has multiplicity of 2.

(x-9) has multiplicity of 3.

so, the zeroes of the polynomial function is given by

[tex]x+9=0\\\\x=-9\\\\x-9=0\\\\x=9[/tex]

Hence, the zeroes are -9,-9, 9, 9, 9.

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