Area of a parallelogram = b × h
Let the heights of first and second parallelogram be h and h' respectively.
Given that,
h = ½h'
Area of first parallelogram= bh ...(i)
Area of second parallelogram = bh'
but, h = ½h'
Replacing h by ½h' in equation (i)
Therefore, area of first parallelogram = ½bh'
Ratio - ½bh' : bh'
= 1:2