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An image of a snowflake is 1.8 centimeters wide. If the actual snowflake is 1/8 the size of the image, what is the width of the actual snowflake?

Respuesta :

dahamivherath
to find the answer you have to divide 1.8 by 8 and multiply by 1 because if you divide the image into 8 pieces,only one piece is the size of a actual snowflake. 

1.8÷8×1=0.225

answer= 0.225cm 

BladeRunner212

0.225 centimeters

Further explanation

Given:

  • An image of a snowflake is 1.8 centimeters wide.
  • The actual snowflake is ¹/₈ the size of the image.

Question:

What is the width of the actual snowflake?

The Process:

Since the actual snowflake is part of the image size by ¹/₈ part, let us create an 8-unit pattern that represents the image.

  • The image of a snowflake in the pattern: [tex]\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot }\boxed{ \cdot } \rightarrow 1.8 \ cm [/tex]
  • The actual snowflake in the pattern: [tex]\boxed{ \cdot } \rightarrow \frac{1}{8} \ of \ 1.8[/tex]

And now, let us find out the width of the actual snowflake. As we know, the actual snowflake is ¹/₈ the size of the image.

The width of the actual snowflake:

[tex]\boxed{ \ = \frac{1}{8} \times 1.8 \ }[/tex]

[tex]\boxed{ \ = \frac{1}{8} \times \frac{18}{10} \ }[/tex]

[tex]\boxed{ \ = \frac{1 \times 18}{8 \times 10} \ }[/tex]

[tex]\boxed{ \ = \frac{18}{80} \ }[/tex]

Both the numerator and denominator are divided by two to make it a simple fraction.

[tex]\boxed{ \ = \frac{9}{40} \ }[/tex]

Both the numerator and denominator are multiplied by 25 to make it a decimal fraction. Therefore, the denominator will be 1,000.

[tex]\boxed{ \ = \frac{9 \times 25}{40 \times 25} \ }[/tex]

[tex]\boxed{ \ = \frac{225}{1,000} \ }[/tex]

Thus, the width of the actual snowflake is 0.225 centimeters.

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Keywords: an image of a snowflake, 1.8 centimeters wide. the actual, 1/8, the size, what is the width, the actual snowflake, simple fraction, decimal, the numerator and denominator

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