we are given
three consecutive even integers
Let's assume
first even integer is x
second even integer is x+2
third even integer is x+4
sum of the first two consecutive even integers is equal to three times the third so, we can get equation as
[tex] x+x+2=3(x+4) [/tex]
now, we can solve for x
[tex] 2x+2=3x+12 [/tex]
[tex] 2x+2=3x+12 [/tex]
[tex] x=-10 [/tex]
so, we get
first integer is -10
second integer is -10+2=-8
third integer is -10+4=-6.................Answer
