suppose you know the base of a rectangle has a length of 12 inches and a diagonal has a lenght of 13 inches. find the area of the rectangle

Respuesta :

We are given

length=l=12inches

diagonal =d=13inches

Let's assume

width=w

so, firstly we need to find width

we know that length , width and diagonal form right angled triangle

so, we can use Pythagoras theorem

[tex] d^2=l^2+w^2 [/tex]

now, we can plug values

[tex] 13^2=12^2+w^2 [/tex]

[tex] w^2=25 [/tex]

[tex] w=5 [/tex]

now, we can find area of rectangle

Area = length*width

[tex] Area=l*w [/tex]

now, we can plug values

[tex] Area=12*5 [/tex]

[tex] Area=60inch^2 [/tex].............Answer

SOLUTION:

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1. Find the missing leg:

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a² + b² = c²

12² + b² = 13²

b² = 13² - 12²

b² = 25

b = √25

b = 5

The missing leg is 5 inches.

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2. Find the area:

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Area = Length x Width

Area = 12 x 5 = 60 in²

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Answer: The area is 60 in².

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