Here given two parallel lines cut by a transversal, so the given two angles are alternate interior angles.
We know that alternate interior angles are equal.
So we can find x by equating the two angles.
[tex] 5x-10 = 4x+10 [/tex]
Now to solve for x, we will move -10 to the right side. To get rid of -10 and to move it to right side we will add 10 to both sides.
[tex] 5x-10+10 = 4x+10+10 [/tex]
[tex] 5x = 4x+20 [/tex]
Now we will move 4x to the left side by subtracting it from both sides.
[tex] 5x-4x = 4x+20-4x [/tex]
[tex] 5x-4x = 20 [/tex]
[tex] x = 20 [/tex]
We have got the required value of x.
The value of x = 20.
