Answer: -
64.0 g/mol
Explanation: -
Volume V = 0.134 L
Pressure P = 0.992 atm
Temperature T = 397 K
Using the combined gas equation
PV = nRT
Number of moles n = [tex] \frac{PV}{RT} [/tex]
= [tex] \frac{0.992 atm x 0.134 L}{0.082 L atm K−1 mol−1 x 397 K} [/tex]
= 0.0041
Mass = 0.261 g
Molar mass = Mass / Number of moles
= [tex] \frac{0.261 g}{0.0041 mol} [/tex]
= 64.0 g / mol