Alright, lets get started.
The given expression is : [tex] 2x^{2} -10 x - 48 [/tex]
Firstly, we could take 2 as common factor out
[tex] 2 (x^{2}- 5x - 24) [/tex]
-5x could be written as -8x + 3x
[tex] 2 (x^{2}- 8x + 3x - 24) [/tex]
Now, taking x common factor out in first two terms and 3 common factor in last two terms
[tex] 2 (x(x- 8) + 3(x - 8)) [/tex]
[tex] 2 (x-8)(x+3) [/tex]
or
[tex] 2 (x+3)(x-8) [/tex]
Answer is option d.
Hope it will help :)