Factor 2x2 − 10x − 48 completely.

a 2(x − 3)(x + 8)
b (2x + 3)(x − 8)
c (2x − 3)(x + 8)
d 2(x + 3)(x − 8)

Respuesta :

Alright, lets get started.

The given expression is : [tex] 2x^{2} -10 x - 48 [/tex]

Firstly, we could take 2 as common factor out

[tex] 2 (x^{2}- 5x - 24) [/tex]

-5x could be written as -8x + 3x

[tex] 2 (x^{2}- 8x + 3x - 24) [/tex]

Now, taking x common factor out in first two terms and 3 common factor in last two terms

[tex] 2 (x(x- 8) + 3(x - 8)) [/tex]

[tex] 2 (x-8)(x+3) [/tex]

or

[tex] 2 (x+3)(x-8) [/tex]

Answer is option d.

Hope it will help :)