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Antoine has $18.20 to spend on some oranges and a pumpkin. Oranges cost $1.30 per pound, and a pumpkin costs $5.20.

The inequality 1.30x + 5.20 ≤ 18.20 models this situation, where x is the number of pounds of oranges.

Solve the inequality. How many pounds of oranges can Antoine buy?

Respuesta :

Peredhel

Hi!

To solve this inequality, we have to isolate x on one side. Whatever we do to the equation we have to do it on both sides.

1.30x + 5.20 ≤ 18.20

Subtract 5.20 from both sides.

1.30x + 5.20 - 5.20 ≤ 18.20 - 5.20

1.30x ≤ 13

Divide by 1.30 on both sides.

1.30x/1.30 ≤ 13/1.30

x ≤ 10

Antoine can buy 10 pounds of oranges.

Hope this helps! :)

The inequality x ≤ 10 represents the Antony can buy 10 pounds of oranges if the Antoine has $18.20 to spend on some oranges and a pumpkin.

What is inequality?

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have an inequality:

1.30x + 5.20 ≤ 18.20

x is the number of pounds of oranges.

1.30x  ≤ 18.20 - 5.20

1.30x  ≤ 13

x  ≤  10

Thus, the inequality x ≤ 10 represents the Antony can buy 10 pounds of oranges if the Antoine has $18.20 to spend on some oranges and a pumpkin.

Learn more about the inequality here:

brainly.com/question/19491153

#SPJ2

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