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A basket contains four apples and five peaches. Three times, you randomly select piece of fruit, returning to the basket, and then mix in the fridge. The first time you get to an apple. Then second and third times you get peaches. Find the probability of this occurring

Respuesta :

Answer:

100/729

Step-by-step explanation:

The basket contains 9 fruits: 4 apples and 5 peaches. Thus the probability of choosing one fruit can easily be determined.

P(Apple is selected) = number of apples / number of fruits= 4/9.

P(Peach is selected) = number of peaches / number of fruits= 5/9.

If the replacement is allowed, then the probabilities will remain unchanged for all the fruits. Therefore, the probability of selecting an apple in the any attempt is 4/9 and the probability of selecting a peach in any attempt is 5/9. Assuming that the selection of the fruits is independent, we can safely multiply the probabilities. Therefore, 4/9 * 5/9 * 5/9 = 100/729.

Therefore, the correct answer is 100/729!!!

The probability of the event occurring is p = 0.159

How to get the probability?

We assume that each fruit has the same probability of being randomly picked.

Now, there are 4 apples and 5 peaches (for a total of 9 fruits).

The first time that you randomly select a fruit you get an apple, the probability of this is given by the quotient between the number of apples and the total number of fruit on the basket, this is:

P = 4/9

The next time you get a peach, the probability is computed in the same way, but now there are 8 fruits on the basket (and 5 peaches) so we have:

Q = 5/8

The last time you also get a peach, and this time there are 4 peaches and 7 frits in total, so the probability is:

K = 4/7

Then the joint probability (the probability of these 3 events happening) is the product of the individual probabilities:

probability = (4/9)*(5/8)*(4/7) = 0.159

If you want to learn more about probability, you can read:

https://brainly.com/question/251701