Respuesta :

DeanR

If we just have

[tex]y = \cos x[/tex]

that's an amplitude of 1 and a period of [tex]2\pi[/tex]

Let's modify this step by step.

Amplitude of 4. Four times the amplitude means a factor of 4 on the outside.

[tex]y = 4 \cos x[/tex]

Period of π. Double the period means a factor of 2 on the inside.

[tex]y = 4 \cos(2x)[/tex]

Horizontal shift of π/2 to the left. To the left means adding a positive number to x. The question appear ambiguous. It's not clear to me if we add to x or 2x; let's make it

[tex]y = 4 \cos(2(x + \frac \pi 2))[/tex]

Vertical shift of 3:

[tex]y = 3 + 4 \cos(2(x + \frac \pi 2))[/tex]

[tex]y = 3 + 4 \cos(2x + \pi)[/tex]

Depending on the interpretation of the phase shift, that pi may be a pi/2.

Answer: [tex]3 + 4 \cos(2x + \pi)[/tex]