Answer: -
9270 grams
Explanation: -
Number of molecules of C₆H₁₂O₆ = 3.25 x 10 ²⁶
According to Avogadro's law,
6.02 x 10 ²³ molecules of C₆H₁₂O₆ are present in 1 mole of C₆H₁₂O₆
3.25 x 10 ²⁶ molecules of C₆H₁₂O₆ are present in [tex] \frac{1 mole C6H12O6 x 3.25 x 10 26 molecules}{6.02 x 10 23 molecules} [/tex] of C₆H₁₂O₆
= 54 mol of C₆H₁₂O₆
Molar mass of C₆H₁₂O₆ = 12 x 6 + 1 x 12 + 16 x 6 = 180g /mol
Mass of C₆H₁₂O₆ = 54 mol x 180g /mol
= 9270 g
Explanation:
[tex]N=n\times N_A[/tex]
Where:
N = Number of particles / atoms/ molecules
n = Number of moles
[tex]N_A=6.022\times 10^{23} mol^{-1}[/tex] = Avogadro's number
We have:
Molecules of glucose, [tex]C_6H_{12}O_6=3.25\times 10^{26} [/tex]
Moles of glucose = n =?
[tex]n=\frac{N}{N_A}=\frac{3.25\times 10^{26}}{6.022\times 10^{23} mol^{-1}}[/tex]
n = 539.69 mol
Mass of 539.69 moles of glucose :
= 539.69 mol × 180 g/mol =97,144.2 g