Answer: -
0.934 moles constitute 5.62 x 1023 formula units of sodium hydroxide.
Explanation: -
6.02 x 10²³ NaOH formula units are present in 1 mole of sodium hydroxide according to Avogadro's Law.
5.62 x 10²³ NaOH formula units are present in[tex] \frac{ 1 mole x 5.62 x 1023}{6.02 x 1023} [/tex]
= 0.934 moles of NaOH
Answer:
[tex]5.62\times 10^{23} [/tex] formula units of sodium hydroxide constitutes 0.934 moles.
Explanation:
Number of molecules of sodium hydroxide =[tex]N=5.62\times 10^{23} [/tex] molecules
Moles of sodium hydroxide = n
[tex]N=n\times N_A[/tex]
[tex]N_A=6.022\times 10^{23} mol^{-1}[/tex]
[tex]5.62\times 10^{23}=n\times 6.022\times 10^{23} mol^{-1}[/tex]
n = 0.934 moles
So, [tex]5.62\times 10^{23} [/tex] formula units of sodium hydroxide constitutes 0.934 moles.
