The first equation given [tex] 6=1-2n+5 [/tex]
We have to add 1 and 5 to the right side first. We will get,
[tex] 6= 6 - 2n [/tex]
To get rid of 6 from the right side we have to subtract 6 from both sides.
[tex] 6-6 = 6-6-2n [/tex]
[tex] 6-6 = -2n [/tex]
[tex] 0=-2n [/tex]
To find n we have to move -2 to the other side by dividing both side by -2.
[tex] 0/-2 = -2n/-2 [/tex]
[tex] 0= n [/tex]
[tex] n=0 [/tex]
So we have got the required answer for the first question.
The solution is n = 0.
The second equation given,
[tex] 8x-2 = -9+7x [/tex]
First we have to move 7x to the left side by subtracting it from both sides.
[tex] 8x-7x-2 = -9+7x-7x [/tex]
[tex] 8x-7x-2 = -9 [/tex]
[tex] x-2 = -9 [/tex]
Now we have to move -2 to the right side by adding 2 to both sides.
[tex] x-2+2 = -9+2 [/tex]
[tex] x = -9+2 [/tex]
[tex] x = -7 [/tex]
We have got the required answer for the second question.
The solution is x = -7.
The third equation given,
[tex] -8 = -(x+4) [/tex]
We have to get rid of that negative sign from both sides. As we have negative sign to both sides we can cancel it out. We will get,
[tex] 8=x+4 [/tex]
Now we have to move 4 to left side by subtracting it from both sides.
[tex] 8-4 = x+4-4 [/tex]
[tex] 8-4 = x [/tex]
[tex] 4=x [/tex]
[tex] x = 4 [/tex]
So we have got the required answer .
The solution is x = 4.
