Its height in feet is represented by f(x)=-16(x^2-6x-16),where x is the number of seconds since the rock is thrown .the height of the rock is 0 feet when it hits water.how long doesit take the rock to hit the water

Respuesta :

here we have [tex] f(x) [/tex] is the height represented in feet.

we need to at when height is zero what will be the time taken to hit the ground.

which means [tex] f(x)=0 [/tex] we need to find x when f(x)=0.

[tex] -16(x^2-6x-16)=0 [/tex]

[tex] (x^2-6x-16)=\frac{0}{-16} =0 [/tex]

we need to use quadratic formula to find x. or factorisation.

if we factor out [tex] x^2-8x+2x-16=0 [/tex]

[tex] x(x-8)+2(x-8)=0 [/tex]

where [tex] (x+2)(x-8)=0 [/tex]

[tex] x=-2,8 [/tex]

where as time cannot be negative so x=8 is the time when height is zero.

Answer:

Its 8 seconds. Trust me.

Step-by-step explanation:

Ive done the quiz on ap3x