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A current of 5.52 a flows along a wire with ℓ = (1.382 i − 2.095 j) m. the wire resides in a uniform magnetic field b = (−0.350 j + 0.550 k) t. what is the magnetic force acting on the wire? (express your answer in vector form.) fb = n

Respuesta :

Magnetic force on a wire inside magnetic field is given by formula

[tex]F = i (L X B)

here we will have

ℓ = (1.382 i − 2.095 j) m

B = (−0.350 j + 0.550 k) t.

i = 5.52 A

now as per above formula we have

[tex]F = 5.52 * (1.382 i − 2.095 j) X (−0.350 j + 0.550 k)[/tex]

[tex]F = 5.52* (-0.4837 k - 0.7601 j - 1.152 i)[/tex]

[tex]F = - 6.36 i - 4.196 j - 2.670 k[/tex]

So magnetic force on the wire is given by above expression with all three components shown with i, j, k.

x component of force is 6.36 N

y component of force is 4.196 N

z component of force is 2.67 N

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