Respuesta :
To solve for x in terms of b, simply treat b as a number, and solve for x as usual: first of all, we expand the left hand side:
[tex] -2bx+10 = 16 [/tex]
Subtract 10 from both sides:
[tex] -2bx = 6 [/tex]
Divide both sides by -2b:
[tex] x = \cfrac{6}{-2b} = \cfrac{-3}{b} [/tex]
This means that in particular, if we set [tex] b= 3 [/tex], we have
[tex] x = \cfrac{-3}{3} = -1 [/tex]
For the given equation ,
the value of x in terms of b is [tex]x=\frac{-3}{b}[/tex]
The value of x when b=3 is -1
Given :
We are given with the equation [tex]-2(bx-5)=16[/tex]
we need to solve for x . Write x in terms of b
Lets isolate x using arithmetic operations
[tex]-2(bx-5)=16[/tex]
Divide both sides by -2
[tex]bx-5=-8[/tex]
Now we add 5 on both sides
[tex]bx=-8+5\\bx=-3[/tex]
Divide both sides by b
[tex]x=\frac{-3}{b}[/tex]
Given :the value of b is 3
Substitute 3 for b
[tex]x=\frac{-3}{b} \\b=3\\x=\frac{-3}{3} \\x=-1[/tex]
Learn more : brainly.com/question/13240062
