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Mr. Albano wants to paint menus on the wall of his cafe in chalkboard paint. The gray area below shows where the rectangular menus will be. Each menu will measure 6ft wide and 7 1/2 ft tall. How many square feet of menu space will Mr. Albano have? What is the area of wall space that is not covered by the chalkboard paint?

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meerkat18
Saw the image.

Given: 
Whole wall is 13 2/3 ft by 25ft
4 menus (gray areas) with measurements of 6 ft wide and 7 1/2 ft tall.

Convert mixed fractions into improper fractions.

13 2/3 ft = ((13*3)+2)/3 = 41/3

Area of the Wall = 41/3 ft * 25 ft = (41*25)/3 = 1025/3 ft² = 341 2/3 ft²

7 1/2 ft = ((7*2)+1)/2 = 15/2

Area of the menu = 15/2 ft * 6 ft = (15*6)/2 = 90/2 = 45 ft²
45 ft² x 4 menus = 180 ft² 


Area of wall space not covered by the chalkboard paint:
A = 341 2/3 ft² - 180 ft² = 161 2/3 ft²

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