Hey There!
Volume = 1.25 L
Molarity = 0.75 M
Therefore:
n = M * V
n = 0.75 * 1.25
n = 0.9375 moles
hope this helps!
Explanation:
Molarity is defined as the number of moles divided by volume of solution in liter.
Mathematically, Molarity = [tex]\frac{no. of moles}{Volume in liter}[/tex]
Since, it is given that molarity is 0.75 M and volume is 1.25 liter. Therefore, calculate the number of moles as follows.
Molarity = [tex]\frac{no. of moles}{Volume in liter}[/tex]
Number of moles = [tex]Molarity \times Volume in liter[/tex]
= [tex]0.75 M \times 1.25 l[/tex]
= 0.937 mol
Thus, we can conclude that number of moles of solute are present in 1.25 l of a 0.75m nano3 solution is 0.937 mol.
