Answer: -
2.5 M
Explanation: -
Volume of NaOH = 25.0 mL
= 25.0/1000 = 0.025 L
Strength of NaOH = 1 M
Number of moles of NaOH = Volume of NaoH x strength of NaOH
= 0.025 L x 1 M
= 0.025 mol
Volume of HCl = 10.0 mL = 10.0/1000 =0.01 L
The balanced chemical equation for the reaction of HCl and NaOH is
HCl + NaOH→ NaCl + H₂O
At the equivalence point,
Number of moles of HCl =Number of moles of NaOH
Strength of HCl x Volume of HCl = 0.025 mol
Strength of HCl x 0.01 L = 0.025 mol
Strength of HCl = 0.025 / 0.01 = 2.5 M
Thus If it takes 25.0 ml of M NaOH solution to standardize 10.0 ml of HCl, 2.5 M is the exact concentration of HCl
