HELP. SUPER EASY MATH PROBLEM. 20 POINTS

First find the area of the sector of 150 degrees:
150/360 x PI * 27.8^2 = 1011.6452 in^2
Now find the area of the triangle formed by the 150 degrees and the radius 27.8
first find the length of the chord ( the base of the triangle)
c^2 = 27.8^2 + 27.8^2 - 2 * 27.8 * cos(150) = 53.71
now find the height by using half the chord length as the base and using the Pythagorean theorem:
26.855^2 - 27.8^2 = height^2
height = 7.19
The area of the triangle is 1/2 x base x height = 1/2 x 26.855 x 7.1952 = 96.605
multiply by 2 because we made 2 right triangles: 96.54 x 2 = 193.21 square inches.
Now the area of the shaded region is the area of the sector minus the area of the triangle:
1011.6452 - 193.21 = 818.4352
Rounded to nearest tenth = 818.4 in^2
The area of the shaded = the area of the sector - the area of the isosceles triangle.
Split the isosceles triangle in half, each of those triangles is a 30-60-90 triangle, where the radius is the hypotenuse.
Ratio of short leg: long leg: hypotenuse= x : x√3 : 2x
Given hypotenuse = radius = 27.8 in
so short leg = 27.8 / 2 = 13.9 in
long leg = 13.9 √3 = 24.1 in
Area of this isosceles triangle = 24.1 x 13.9 = 334.99 in^2
Area of sector = (150 / 360) π r^2
= (150 / 360) (3.14) (27.8)^2
= 0.4 * (3.14) (772.84)
= 970.7 in^2
Area of shaded = 970.7 in^2 - 334.99 in^2 = 635.71 in^2
= 635.7 in^2 (nearest tenth)
Answer:
635.7 in^2